Youtor
DAY 18 LeetCode 566 Reshape the Matrix dsa consistency
>> YOUR LINK HERE: ___ http://youtube.com/watch?v=2QRaFjnyqWw
@CodeWithPoojagupta Hey, everyone! 👋 Welcome to Code_With_Pooja, your go-to channel for mastering DSA concepts and coding skills! In today’s video, we’ll tackle a fun and frequently asked problem on LeetCode: Reshape the Matrix (Problem 566). This question challenges us to reshape a matrix while keeping the data intact and is a great exercise in understanding 2D arrays and how to manipulate data in different formats. • In this video, we’ll go over: • Problem Description: We’re given a matrix mat and two integers r and c. Our task is to reshape the matrix into dimensions of r x c if possible, while maintaining the original data in a row-traversal order. If the reshape isn’t feasible, we return the original matrix. • Examples to Understand the Requirements: I’ll walk you through sample input and output examples so you can fully understand how reshaping works in different cases. • Constraints to Consider: From matrix sizes to value limits, we’ll review all constraints to ensure our solution handles all edge cases. • Step-by-Step Java Code Explanation: We’ll write the code from scratch, breaking down each line to make it as easy as possible. We’ll start by checking if reshaping is feasible and then go through the process of flattening and rebuilding the matrix using loops. • Complexity Analysis: Finally, we’ll analyze the time and space complexity of our solution so you understand how efficient the code is. • java • Copy code • // Java Solution Snippet: • public int[][] matrixReshape(int[][] mat, int r, int c) { • int size = mat.length * mat[0].length; • if (size != r * c) { • return mat; • } • int[] mat1 = new int[r * c]; • int k = 0; • for (int i = 0; i less mat.length; i++) { • for (int j = 0; j less mat[i].length; j++) { • mat1[k++] = mat[i][j]; • } • } • int[][] mat2 = new int[r][c]; • k = 0; • for (int i = 0; i less r; i++) { • for (int j = 0; j less c; j++) { • mat2[i][j] = mat1[k++]; • } • } • return mat2; • } • 🔥 Highlights of the Solution: • Validating if reshaping is possible by comparing total elements. • Flattening the original matrix into a 1D array. • Restructuring the 1D array back into the new 2D format. • Make sure to follow along as I explain each step and the logic behind it. After watching, you'll be able to confidently tackle similar matrix problems on your own! • 👍 If you found this helpful, don’t forget to like the video, subscribe for more coding content, and share it with friends! Let’s keep growing and learning together on Code_With_Pooja! • Happy Coding! 💻😊
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