Predict the molecular geometry of BF3 boron trifluoride
>> YOUR LINK HERE: ___ http://youtube.com/watch?v=DeZ3PxbzX58
A BF3 molecule is trigonal planar, because it's three fluorine atoms around a central boron atom, and that boron has no lone pairs on it. This gives it AX3 VSEPR geometry. The bond angles are 120 degrees. • NOTE: In a crystal structure, these molecules pack together and each boron touches against a fluorine atom from a different molecule. This would give it a tetrahedral geometry. • Check me out: http://www.chemistnate.com
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