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de broglies wavelength calculation simple problem electron in accelerated potential
>> YOUR LINK HERE: ___ http://youtube.com/watch?v=NAa-lPSDyko
Determine the de-Broglie’s wavelength of an electron that has been accelerated through a potential difference of 100V. • 𝒉=𝟔.𝟔𝟑×𝟏𝟎^(−𝟑𝟒) 𝑱.𝒔 • 𝑚𝑒=9.11 x 10^(−31) • 𝑞𝑒=1.607×10^(−19) • Equation used during solution are • E=qv • E=1/2mv sqaure • Finally • lambda = h/p de broglie wavelength of electron accelerated in a potential. • Error in calculation • The momentum value presented in the video is not correct do the calculation yourself • the momentum value is p =5.4x10^-24 • #de-broglie #wavelength #acceleratedelectron #electroninacceleratedpotential
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