How to find the Oxidation Number for N in N2F4

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To find the correct oxidation state of N in N2F4 (Dinitrogen tetrafluoride or Tetrafluorohydrazine), and each element in the molecule, we use a few rules and some simple math. • First, since the N2F4 molecule doesn’t have an overall charge (like NO3- or H3O+) we could say that the total of the oxidation numbers for N2F4 will be zero since it is a neutral molecule. • We write the oxidation number (O.N.) for elements that we know and use these to figure out oxidation number for N. • • --------- • RESOURCES • How to Find Oxidation Numbers (rules and examples): • How to Find Oxidation Numbers (Rules... • Oxidation Numbers Practice: • Finding Oxidation Numbers Practice Pr... • ---------- • GENERAL RULES • Free elements have an oxidation state of zero (e.g. Na, Fe, H2, O2, S8). • In an ion the all Oxidation numbers must add up to the charge on the ion. • In a neutral compound all Oxidation Numbers must add up to zero. • Group 1 = +1 • Group 2 = +2 • Hydrogen with Non-Metals = +1 • Hydrogen with Metals (or Boron) = -1 • Fluorine = -1 • Oxygen = -2 (except in H2O2 or with Fluorine) • Group 17(7A) = -1 except with Oxygen and other halogens lower in the group • ----------

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