Hofmann Elimination Amine to Alkene aka Exhaustive Methylation











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1. Add excess CH3I (methyl iodide) to make -NH2 into -N(CH3)3+ • 2. Addition of Ag2O will precipitate AgI and leave OH- leftover • 3. OH- will help perform E2 elimination with N(CH3)3 as leaving group. • Check me out: http://www.chemistnate.com

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