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#python interview questions#python interview questions and answers#python interview questions for freshers#python interview#python interview questions and answers for freshers#python developer interview questions#python interview questions and answers for experienced#top python interview questions#python coding interview questions#python programming interview questions#python interview preparation#python interview coding questions#python job interview# • python interview questions#python for beginners in telugu#python interview questions in telugu#python in telugu#python interview#python interview questions for freshers#python tutorial telugu#python interview telugu#python telugu tutorials#python interview queations telugu#telugu computer world python#python programming interview#python telugu#python full course in telugu#python coding interview questions#telugu python language#python#python tutorial# • ====================================================== • let's break down what this code does: • ```python • li = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] • k = 0 • print(li[k:] + li[:k]) • ``` • Here, `li` is a list containing the numbers from 1 to 10, and `k` is initialized to 0. • Now, let's analyze the statement: • ```python • print(li[k:] + li[:k]) • ``` • Slicing in Python: • In Python, you can use slicing to get a subset of a list. The syntax for slicing is `list[start:stop:step]`, where: • `start`: The starting index of the slice (inclusive). • `stop`: The ending index of the slice (exclusive). • `step`: The step value (optional). • Explanation: • 1. `li[k:]`: This slice starts from index `k` and goes to the end of the list. In this case, it starts from index 0 and goes to the end of the list. So, `li[k:]` returns `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`. • 2. `li[:k]`: This slice starts from the beginning of the list and goes up to (but not including) index `k`. In this case, it starts from the beginning and goes up to index 0. As a result, `li[:k]` returns an empty list `[]`. • 3. `li[k:] + li[:k]`: Now, we concatenate the two slices. `li[k:]` provides the elements from index 0 to the end, and `li[:k]` provides the elements from the beginning up to index 0. So, the concatenation of these slices is the original list itself. • Let's execute the code: • ```python • li = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] • k = 0 • print(li[k:] + li[:k]) • ``` • Output: • ``` • [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] • ``` • So, the result is the same as the original list `li`, `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`. • Here's the detailed explanation: • 1. `li = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`: This line initializes a list named `li` containing the numbers from 1 to 10. • 2. `k = 0`: This line initializes a variable `k` to 0. • 3. `print(li[k:] + li[:k])`: This line prints the result of slicing the list and concatenating the slices. Let's break it down further: • `li[k:]`: This slice starts from index `k` (0 in this case) and goes up to the end of the list. • When `k = 0`, `li[k:]` returns `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`. • `li[:k]`: This slice starts from the beginning of the list and goes up to (but not including) index `k`. • When `k = 0`, `li[:k]` returns an empty list `[]`. • `li[k:] + li[:k]`: The concatenation of the two slices. • When `k = 0`, the concatenation of `li[k:]` and `li[:k]` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10] + []`, which gives `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`. • So, when `k = 0`, `print(li[k:] + li[:k])` outputs: • ``` • [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] • ``` • It essentially prints the original list `li`. This is because `k` is 0, so the concatenation of `li[k:]` and `li[:k]` is the entire list `li`. • Here's the detailed explanation: • 1. `li = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`: This line initializes a list named `li` containing the numbers from 1 to 10. • 2. `k = 0`: This line initializes a variable `k` to 0. • 3. `print(li[k:] + li[:k])`: This line prints the result of slicing the list and concatenating the slices. Let's break it down further: • `li[k:]`: This slice starts from index `k` (0 in this case) and goes up to the end of the list. • When `k = 0`, `li[k:]` returns `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`. • `li[:k]`: This slice starts from the beginning of the list and goes up to (but not including) index `k`. • When `k = 0`, `li[:k]` returns an empty list `[]`. • `li[k:] + li[:k]`: The concatenation of the two slices. • When `k = 0`, the concatenation of `li[k:]` and `li[:k]` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10] + []`, which gives `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`. • So, when `k = 0`, `print(li[k:] + li[:k])` outputs: • ``` • [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] • ``` • It essentially prints the original list `li`. This is because `k` is 0, so the concatenation of `li[k:]` and `li[:k]` is the entire list `li`.

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