Motion NCERT Exercises Class 9 Physics
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πPrevious Video: • Uniform Circular Motion (UCM) - Motio... • πNext Video: • Force and Laws of Motion - Introducti... • βοΈππ Watch Full Free Course: https://www.magnetbrains.com • βοΈππ Get Any Class Subject's Topic Video Here:- https://www.magnetbrains.com/get-topi... • βοΈππ Get All Subjects Playlists: βhttps://www.pabbly.com/out/all-videos... • βοΈππ Grab Notes by Expert Teachers Here: https://www.pabbly.com/out/magnet-brains • βοΈππ Place Your Queries For Books Here: https://www.magnetbrains.com/booklet • βοΈππ Get Books Prepared by Our Expert Teachers at Your Door Step: https://www.magnetbrains.com/book_pur... • =============================================== • π’ Full Playlist Link: • Class 9 Physics (New Session 2023-24)... • β In this video, • βοΈ Class: 9 • βοΈ Subject: Physics • βοΈ Chapter: Motion • βοΈ Topic Name: NCERT Exercises • =============================================== • 00:00 Physics Introduction: Motion • 00:18 NCERT Exercises Question 1 • 05:48 Question 2 • 10:26 Question 3 • 12:02 Question 4 • 12:34 Numericals Questions 1 • 14:59 Question 2 • 17:13 Website Overview • =============================================== • π’ π₯ Available (Kindergarten to 12th) all Video Subject wise Playlist https://www.pabbly.com/out/all-videos... • Why study from Magnet Brains? • Magnet Brains is an online education platform that helps give You NCERT/CBSE curriculum based free full courses from Kindergarten to Class 12th so that you can perform well in any and all exams you give in your academic career. • πContact us π€π€ • β‘οΈ Connect with us : [email protected] • β‘οΈ Website : https://www.magnetbrains.com/ • β‘οΈ Subscribe to us on YouTube: / @magnetbrainseducation • β‘οΈ Subscribe to Magnet Brains Hindi Medium : / @magnetbrainshindimedium • β‘οΈ Facebook : https://pabbly.com/out/facebook • β‘οΈ Instagram : https://pabbly.com/out/instagram • β‘οΈ Telegram : http://pabbly.com/out/telegram • Points covered in this video:- • Question 1. An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 minutes 20 s? • Solution: Here, Total time = 2 minutes 20 seconds • = 2 x 60 seconds + 20 seconds • = 120 seconds + 20 seconds • = 140 s • Now, in 40 s, the number of rounds completed = 1 • So, in 140 s, the number of rounds completed = 1 x 140 = 3.5 • (a) Calculation of distance covered in 3.5 rounds • The diameter of circular track is given to be 200 m, so the radius (r) of the circular track will be half of it, which is 200/2 = 100 m • Now, Distance covered in 1 round = Circumference of circular track • = 2πr • = 2 x (22/7) x 100 m (Because π = 22/7) • = 328.57 m • And, Distance covered = 628.57 x 3.5 m • In 3.5 rounds = 2200 m • (b) Calculation of displacement in 3.5 rounds • The athlete makes three and a half rounds (3.5 rounds) of the circular track. Now, if the athlete start from point A (see figure), then after three complete rounds, he will reach at the same point A. and when the athlete again starts from point A and makes the remaining half round, he will reach point B (which is diametrically opposite to A). so, the displacement of athlete will be equal to diameter of the circular track which is 200 m. . • Disclaimer: This video is for educational and informational purposes only and is not intended to infringe on any copyrights. If you believe that this video has used any copyrighted material in a way that constitutes copyright infringement, please contact us at [email protected] and we will take appropriate action.
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