Motion NCERT Exercises Class 9 Physics











>> YOUR LINK HERE: ___ http://youtube.com/watch?v=oox-apEphks

πŸ‘‰Previous Video:    • Uniform Circular Motion (UCM) - Motio...   • πŸ‘‰Next Video:    • Force and Laws of Motion - Introducti...   • βœ”οΈπŸ“šπŸ‘‰ Watch Full Free Course: https://www.magnetbrains.com • βœ”οΈπŸ“šπŸ‘‰ Get Any Class Subject's Topic Video Here:- https://www.magnetbrains.com/get-topi... • βœ”οΈπŸ“šπŸ‘‰ Get All Subjects Playlists: ​https://www.pabbly.com/out/all-videos... • βœ”οΈπŸ“šπŸ‘‰ Grab Notes by Expert Teachers Here: https://www.pabbly.com/out/magnet-brains • βœ”οΈπŸ“šπŸ‘‰ Place Your Queries For Books Here: https://www.magnetbrains.com/booklet • βœ”οΈπŸ“šπŸ‘‰ Get Books Prepared by Our Expert Teachers at Your Door Step: https://www.magnetbrains.com/book_pur... • =============================================== • πŸ“’ Full Playlist Link:   • Class 9 Physics (New Session 2023-24)...   • βœ… In this video, • βœ”οΈ Class: 9 • βœ”οΈ Subject: Physics • βœ”οΈ Chapter: Motion • βœ”οΈ Topic Name: NCERT Exercises • =============================================== • 00:00 Physics Introduction: Motion • 00:18 NCERT Exercises Question 1 • 05:48 Question 2 • 10:26 Question 3 • 12:02 Question 4 • 12:34 Numericals Questions 1 • 14:59 Question 2 • 17:13 Website Overview • =============================================== • πŸ“’ πŸ”₯ Available (Kindergarten to 12th) all Video Subject wise Playlist https://www.pabbly.com/out/all-videos... • Why study from Magnet Brains? • Magnet Brains is an online education platform that helps give You NCERT/CBSE curriculum based free full courses from Kindergarten to Class 12th so that you can perform well in any and all exams you give in your academic career. • πŸ‘‰Contact us πŸ€‘πŸ€‘ • ➑️ Connect with us : [email protected] • ➑️ Website : https://www.magnetbrains.com/ • ➑️ Subscribe to us on YouTube:    / @magnetbrainseducation   • ➑️ Subscribe to Magnet Brains Hindi Medium :    / @magnetbrainshindimedium   • ➑️ Facebook : https://pabbly.com/out/facebook • ➑️ Instagram : https://pabbly.com/out/instagram • ➑️ Telegram : http://pabbly.com/out/telegram • Points covered in this video:- • Question 1. An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 minutes 20 s? • Solution: Here, Total time = 2 minutes 20 seconds • = 2 x 60 seconds + 20 seconds • = 120 seconds + 20 seconds • = 140 s • Now, in 40 s, the number of rounds completed = 1 • So, in 140 s, the number of rounds completed = 1 x 140 = 3.5 • (a) Calculation of distance covered in 3.5 rounds • The diameter of circular track is given to be 200 m, so the radius (r) of the circular track will be half of it, which is 200/2 = 100 m • Now, Distance covered in 1 round = Circumference of circular track • = 2πr • = 2 x (22/7) x 100 m (Because π = 22/7) • = 328.57 m • And, Distance covered = 628.57 x 3.5 m • In 3.5 rounds = 2200 m • (b) Calculation of displacement in 3.5 rounds • The athlete makes three and a half rounds (3.5 rounds) of the circular track. Now, if the athlete start from point A (see figure), then after three complete rounds, he will reach at the same point A. and when the athlete again starts from point A and makes the remaining half round, he will reach point B (which is diametrically opposite to A). so, the displacement of athlete will be equal to diameter of the circular track which is 200 m. . • Disclaimer: This video is for educational and informational purposes only and is not intended to infringe on any copyrights. If you believe that this video has used any copyrighted material in a way that constitutes copyright infringement, please contact us at [email protected] and we will take appropriate action.

#############################









Content Report
Youtor.org / YTube video Downloader Β© 2025

created by www.youtor.org